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posted by Michael .
A ladder 10 ft long rests against a vertical wall. If the bottom of the ladder slides away from the wall at a rate of 2 ft/s, how fast is the angle between the ladder and the ground changing when the bottom of the ladder is 5 ft from the wall? Evaluate your answer numerically. (Round the answer to three decimal places.)

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bobpursley
let x be the horizontal distance from wall to ladder.
cosineTheta=x/10
10 cosTheta=x
10sinTheta dTheta/dt= dx/dt
so you are looking for dTheta/dt
when x=5, theta = arccos.5, or 60 deg, and sin of 50 = .877
dTheta/dt= dx/dt / (10*.877)
check all that. 
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Jen
.228
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