11th grade
posted by john .
A 625kg racing car completes one lap in 14.3 s around a circular track with a radius of 50.0 m. The car moves at constant speed.
(a) What is the acceleration of the car?

Your SUBJECT is not 11th grade.

yes it is

acceleration= V^2/r
v=PI*r*2/14.3
so acceleration= PI^2*4*r/14.3 put r in.
check my algebra. 
Centripetal Acceleration = v^2/r
= (circumference/time)^2/r
= (2*pi*r/t)^2)/r
= ((2*3.14*50/14.3)^2)/50
= 9.64 m/s^2 
Thank you! you are correct @carey
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