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Rectangle ABCD has diagonals AC and BD. E is the point of intersection of the two diagonals. If the area of triangle AEB is 8, what is the area of triangle ACD?

  • Geometry -

    ACD has half the area if the rectangle.

    AEB is less than half of the rectangle, and its fraction of the whole depends upon the aspect ratio (AB/BC) of the triangle.

    More information is needed to answer the question.

  • Geometry -

    In a rectangle, the diagonals bisect each other giving you four triangles of equal area.
    so triangle ACD = 16

  • Geometry -

    Whoops! I forgot that equal-area theorem. Thanks again, Reiny.

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