Calculus
posted by Amy .
Use a linear approximation (or differentials) to estimate the given number.
(32.06)^4/5

f= (x+a)^4/5
df= 4/5(x+a)^1/5 *da
df appx= 4/5 (1/2)*.06=.024
f=appx 16+.024= 16.024 
[32(1 + 0.1875)]^0.8
= (32^0.8)*(1 + 0.001875]^0.8
= 16* (1 + 0.8*0.001875 +...]
= 16*(1.0015 + ...) = 16.024