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A worker pushes a wheelbarrow with a force of 40 N over a level distance of 6.0 m. If a frictional force of 24 N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

  • physics -

    worker work=40*6=240j
    frictionwork:24*6=144j

    net work= difference.

  • physics -

    aw

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