Post a New Question

physics

posted by .

To push a 25.0kg crate up a frictionless surface incline angled at 25 degrees to the horizontal, a worker exerts a force of magnitude 209N parallel to the incline. As the crate slides 1.50m, how much work is done on they crate by (a) the worker's applied force, (b) the gravitational force on the crate, and (c) the normal force exerted by the incline on the crate? (d) what is the total work done?

How do I get started?

  • physics -

    work: 209*1.5 joules total
    normal force=mgSin25
    gravitational force on crate=mg
    workers force=209

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question