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physics

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A car is traveling at 45.0 mi/h on a horizontal highway.
(a) If the coefficient of static friction between road and tires on a rainy day is 0.100, what is the minimum distance in which the car will stop?
____ m

(b) What is the stopping distance when the surface is dry and µs = 0.602?
_____ m

  • physics -

    Vf^2=Vi^2+2ad

    but a= force/mass= mu*mg/m= mu*g
    solve for distance d.

  • physics -

    45 mi/h = 20.1168 m/s

    ma= .100n
    a = .100(g)

    solving for time
    v=vo + at
    20.1168m/s=0+.98(t)
    t=20.527s

    solving for distance
    d=do+vot+at^2/2
    d= 0+0+.98(20.527s)^2/2
    d= 206.469m

  • physics -

    S=u^2/2µs(g)
    S=(20.1168m/s)^2/2*.602*9.8
    S=34.298m

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