physics
posted by Corey .
A grinding wheel 0.40 m in diameter rotates at 2200 rpm.
What is the acceleration of a point on the edge of the grinding wheel?

centripetal acceleration= w^2 r
w = 2PI*2200r/min*1min/60sec
posted by Corey .
A grinding wheel 0.40 m in diameter rotates at 2200 rpm.
What is the acceleration of a point on the edge of the grinding wheel?
centripetal acceleration= w^2 r
w = 2PI*2200r/min*1min/60sec