# math

posted by peter

please can you help me solve the following equations and please can you show your method. thanks

1) 4x+3/5x-6 = x-1/x-6
2) 4x-5/1-6x = x+10/x-6

thanks once again

1. Reiny

If I solve it the way you typed it .....

1. LCD is 5x, so multiply each term by 5x

20x^2 + 3x^2 - 30x = 5x^2 - 5 - 30x
etc

Somehow I have a feeling you meant
(4x+3)/(5x-6) = (x-1)/(x-6)
cross-multiply
5x^2 - 5x - 6x + 6 = 4x^2 - 24x + 3x - 18
x^2 + 10x + 24 = 0
(x+6)(x+4) = 0
x = -6 or x=-4

Do the second one the same way

## Similar Questions

1. ### math ALGEBRA

Solve by either the substitution method or the addition or subtraction method 2m=n-3 3m=2n-9 Just replace n with (2m + 3) in the second equation. Then solve for m. Once you know the value of m, use either of your equations, such as …
2. ### Math - Algebra

A. Solve the following quadratic equations. Make sure to show all your work. Do not use any method (e.g. factoring, completing the square, quadratic formula, graphing) more than twice. Use the graphing method at least once. 1. 3x+2 …
3. ### math

solve each of the following equations by the square root method and show your work (3x + 2)²=8
4. ### math

solve each of the following equations by the square root method and show your work 4x²-20=0
5. ### math

solve each of the following equations by the square root method and show all your work

7. ### Math

solve the system of linear equations using the addition method. Can you please show me the steps on how you reached the answer. Thank You 2x+20y= -144 12x+5y= 56
8. ### Math

I am stuck on trying to figure out how to do this question. Could someone please show me 5 necessary steps ?
9. ### maths

Solve the following differential equation: (1 + x)*(dy/dx) = y where y is a funtion of X solve by the following: A)series expansion B) elemantary method please show working
10. ### mathematics

Solve the following differential equation: (1 + x)*(dy/dx) = y where y is a funtion of X solve by the following by: A)series expansion B) elemantary method please show working

More Similar Questions