Question

(5^-1p^4)^-2

(3y^-4)^2

Answer 1

5^-1 = 1/5, therefore

(5^-1p^4)^-2 = (p^4/5)^-2 = (5/p^4)^2 = 25/p^8

(3y^-4) = (1/3y)^4, therefore

(3y^-4)^2 = (1/3y)^8