Physics

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A 285-kg load is lifted 22.0 m vertically with an acceleration a=0.170 g by a single cable.

Determine the tension in the cable. (N)

Determine the net work done on the load. (J)

Determine the work done by the cable on the load.

Determine the work done by gravity on the load.

Determine the final speed of the load assuming it started from rest.

  • Physics -

    tension=mg+ma

    work done= force*distance

  • Physics -

    3240 N

  • Physics -

    Force due to tension = mg + ma
    The force that the load originally has in addition to the force due to acceleration.

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