chemistry

posted by .

What volume (in Liters) of hydrogen must react to form 17.0L of ammonia according to the following balanced equation:

N2(g) + 3H2(g) --> 2NH3(g)

Ratio from equation is H : NH3 = 3 : 2 = 3/2 : 1 = 17x3/2 : 17 = 25.5 : 17
17 L of hydrogen

can you check my work is this right?

  • chemistry -

    Is what right. In my class I wouldn't give you credit ALTHOUGH the correct number is in there. It's just mixed up with a bunch of other numbers.
    How in the world do you multiply 17 x 3/2 and get 17? The answer is 17 x 3/2 = 25.5 L which you had in your garbled math but the way you've presented it makes the answer unclear.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia?
  2. Chemistry

    Hydrogen gas, , reacts with nitrogen gas, , to form ammonia gas, , according to the equation 3H2+N2-2NH3 How many grams of are needed to produce 13.75g of NH3 ?
  3. college chemistry

    What volume (in Liters) of hydrogen must react to form 17.0L of ammonia according to the following balanced equation: N2(g) + 3H2(g) --> 2NH3(g) Assume an excess of N2 and that all are at the same temperature and pressure.
  4. chemistry

    Determine how many liters of nitrogen will be required to produce 87.0 liters of ammonia. The balanced equation for this reaction is: 3H2(g) + N2(g) ==> 2NH3(g).
  5. Please help me!!!!

    2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer …
  6. Chem Help please!!!!!

    2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer …
  7. Chem- REALLY URGENT!!!

    2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer …
  8. Adv AP Honors Chemistry

    2. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer …
  9. Chemistry ASAP

    3. Methane (CH4), ammonia (NH3), and oxygen (O2) can react to form hydrogen cyanide (HCN) and water according to this equation: CH4 + NH3 + O2  HCN + H2O You have 8 g of methane and 10 g of ammonia in excess oxygen. Answer …
  10. chemistry

    QUESTION 11 Ammonia gas is formed from nitrogen gas and hydrogen gas, according to the following equation: N2 (g) + 3H2 (g) Imported Asset 2NH3 (g). If 84.0 g of nitrogen gas is allowed to react with an excess of hydrogen gas to produce …

More Similar Questions