algerbra
posted by donna .
the length of a rectangular jewlery box is 6 inches more than twice the width. the perimeter is 54 inches find length and width.

Solve the following:
L = 2W + 6
2(L + W) = 54
Rewrite them as:
2W + 2L = 54
2W  L = 6
Subtract the last equation from the third equation. You get an equation in L only.
3L = 60.
Take it from there.
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