this is probablt really simple, but for some reason I can't find out how to do it...
solve for b;
2a/bc= 12
(show your work)
multiply both sides by b, then divide both sides by 12
Multiply both sides by b.
2a/c = 12b
Divide both sides by 12 and reduce.
a/6c = b
To solve for b in the equation 2a/bc = 12, you can follow these steps:
Step 1: Multiply both sides of the equation by bc to isolate b on the left side.
(2a/bc) * bc = 12 * bc
Step 2: Simplify the equation by canceling out bc on the left side and multiplying 12 with bc on the right side.
2a = 12bc
Step 3: Divide both sides of the equation by 12c to isolate b.
(2a) / (12c) = (12bc) / (12c)
Step 4: Simplify the equation further and cancel out 12 with 2 on the left side.
a / (6c) = b
Therefore, the solution for b is:
b = a / (6c)
So, to solve for b in the equation 2a/bc = 12, you divide a by 6c.