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can you answer this please about sums and differences of a rational algebraic expression this is the problem 5/x-7 - x-1/x-7 - 2+x/x-7 another is x+1/2 - x-2/3 + 2x-1/9 another is 2x+3/3 - 3x-1/2 + x-4/12

  • math -

    did you mean
    5/(x-7) - (x-1)/(x-7) - (2+x)/(x-7)

    since you already have a common denominator, just add/subtract the numerators

    = (5 - x + 1 - 2 - x)/(x-7)
    = (4-2x)/(x-7)


    for the second, your common denominator would be the LCM of 2,3, and 9 which would be 18
    (x+1)/2 - (x-2)/3 + (2x-1)/9
    = [9(x+1) - 6(x-2) + 2x-1 ] /9
    = .....

    third one is just as easy, the LCD is 12

  • correction - math -

    obviously I have a typo in the second question, should say ...

    (x+1)/2 - (x-2)/3 + (2x-1)/18
    = [9(x+1) - 6(x-2) + 2x-1 ] /18
    = .....

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