A golf ball is driven, by Emilee, horizontally from an elevated tee with a velocity of 90.65 km/hr. It strikes the fairway 6.34 sec later.
How far has it fallen vertically? and how did u find it please
How high is any object that takes 6.34 sec to fall?
h=1/2 g t^2
thank you sir/ma'am lol :] left my book n note card at school ...fail
To find how far the golf ball has fallen vertically, we need to calculate the vertical distance it has traveled in 6.34 seconds. We can use the equations of motion to find this distance.
The equation for vertical distance traveled (h) is given by the formula:
h = ut + (1/2)gt^2
Where:
h = vertical distance traveled,
u = initial vertical velocity (which is 0 as the ball is driven horizontally),
t = time taken, and
g = acceleration due to gravity.
In this case, since the ball is driven horizontally, the initial vertical velocity (u) is 0. The acceleration due to gravity (g) is approximately 9.8 m/s^2.
Converting 90.65 km/hr to m/s:
90.65 km/hr * (1000 m/1 km) * (1 hr/3600 s) = 25.18 m/s (rounded to two decimal places)
Substituting the given values into the equation, we get:
h = 0 * 6.34 + (1/2) * 9.8 * (6.34)^2
h ≈ 0 + 0.5 * 9.8 * 40.1956
h ≈ 0 + 196.07888
h ≈ 196.08 meters (rounded to two decimal places)
Therefore, the golf ball has fallen vertically approximately 196.08 meters.
To find the vertical distance the golf ball has fallen, we can use the equation of motion for the vertical direction:
d = (1/2) * g * t^2
where:
d is the vertical distance fallen,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
and t is the time it takes for the ball to strike the fairway.
First, let's convert the initial velocity of the golf ball from km/hr to m/s:
90.65 km/hr = (90.65 * 1000) / 3600 m/s ≈ 25.18 m/s
Next, we can use the fact that the ball was driven horizontally to determine how long it took to strike the fairway. Since there is no vertical acceleration due to gravitational force acting horizontally, the time taken to strike the fairway will be the same as the time taken to move horizontally. Therefore, we have:
t = 6.34 sec
Now we can substitute the values into the equation:
d = (1/2) * g * t^2
= (1/2) * 9.8 * (6.34)^2
≈ 186.38 meters
So, the ball has fallen vertically approximately 186.38 meters.
To find the answer, we used the formula for vertical motion and substituted the values of initial velocity, time, and acceleration due to gravity.