Physics

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A long jumper leaves the ground at an angle of 20 degrees and travels a horizontal distanceof 7.0m before landing. What is the takeoff speed of the jumper?
To be honest I really don't know how to solve it. A step-by-step explantion would be helpful.

  • Physics -

    Horizontal:
    7=viCos20*timeinair
    timeinair=7/Vicos20

    Vertical:
    hf=hi+ViSin20*t-4.9t^2
    put the timeinair expression in for time
    0=0+ViSin20(7/cos20)-4.9(49/cos^2 20)

    compute Vi

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