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What's the domain of √((x-2)/(x^2+x-6))

(2,infinity] ?

  • math -

    The proposed answer is good for √(x-2).
    However, since the denominator becomes negative between -2 and 1, the expression in the square-root radical is therefore positive on this interval.
    So the domain can be revised to [2,∞)∪(-2,1).
    Note that +2 is within the domain, because the denominator becomes zero. However, -2 and 1 are excluded because the denominator becomes zero.

  • math -

    When I factor out the bottom its x=-3 and x=2, how did you get -2 and 1? Why is +2 included? Doesn't it become undefined when x=2?

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