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In the explosion of a hydrogen-filled balloon, 0.54 g of hydrogen reacted with 6.6 g of oxygen to form how many grams of water vapor?

  • chem -

    Figure the moles of each.
    .54/2=.27 moles H2
    6.6/32=.21moles O2
    Balance the reaction:

    2H2+O2>>2H2O

    well, you need twice as much H2 as O2, so H2 is the limiting reactant. Use the limiting reactant.

    .27molesH2 (2moleswater/2molesH2)=.27moleswater

    figure the mass of .27 moles water

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