Math
posted by Beth Anne .
Determine the zeros of the function 3x^2 8=10x. I know I rewrite it as 3x^2 10x8 = 0
But then what do I doI'm totally confusedAnswers are
{2,4}
{2,4}
{2/3,4}
{2/3,4}
Please direct me or show the steps, just don't give me the answer because I still won't get it.I think it is 2/3,4 but I'm not sureeven if that is correct, please show me the steps.
Thank you

I would factor it.
(3x+2)(x4)=0
x= 2/3, or x=4 
3x^2  10x  8 = 0,
Factor using the A*C Method:
A * C = 3 * 8 = 24 = 2 * 12,
3x^2 + (2x  12x)  8 = 0.
Group the 4 terms into factorable pairs:
(3x^2  12x) + (2x  8) = 0,
3x(x  4) + 2(x  4) = 0,
Factor (x  4) from each term:
(x  4) (3x + 2) = 0,
x  4 = 0,
x = 4.
3x + 2 = 0,
3x = 2,
x = 2/3.
Solution set: x =2/3, and x = 4.
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