Math SCREAMING for HELP

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Use the quadratic formula to slove the equation.
x^2-x=-7
This is what I have got so far and I do not think this is right:
x=1(-1)±√-1^2-4(1)(7)/2(1)
x=1±√1-4(7)/2
x=1±√-21/2
x=1±-21/2
and here I am lost!

Use rational exponents to simplify. √(5&x^10 )

Simplify by taking roots of the numerator and the denominator. Assume that all expressions under radicals represent positive numbers. ∛(〖125x〗^11/y^3 )

Multiply. (-2t)^2 (〖3t〗^7 )²

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  • Math SCREAMING for HELP -

    change it to the standard form first

    x^2 - x + 7 = 0
    a=1, b=-1, c = 7

    x = (1 ± √(1 - 4(1)(7))/2
    = (1 ± √-27)/2

    Your answer is an imaginary number or called a complex number, you could rewrite is as
    x = (1 ± 3√3 i)/2

  • Math SCREAMING for HELP -

    x^2-x+7=0


    x= (1+-sqrt(1-28))/2=1/2 +- 1/2 sqrt-21

    and sqrt-21= isqrt21

    2) I don't understand the others.

  • Math SCREAMING for HELP -

    Okay so do I write the answer as the solution set is:(1 } 3ã3 i)/2 , 0

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