physics
posted by Anonymous .
After a golf ball is hit it takes off with an initial speed of 22.0 m/s and at an angle of 38.0° with respect to the horizontal. The golf field is flat and horizontal. Neglecting air resistance how far will the golf ball fly?

find time in air:
hf=hi+22Sin38*t4.9t^2
solve for time in the air, t, when height final hf is zero.
horizontal: distance=2cos38 * timeinair. 
How high will the golf ball rise?
im not sure how to do that one 
Max altitude?
1) What is altitude at TimeinAir/2 ?
hf=hi+22Sin38*t4.9(t/2)^2
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