Chem- bobpursley

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What mass of protons would be required to just neutralize the charge of 1.5 g of electrons?

my teacher said .0015kg times 1e-/.00091e-27kg times 1pt/1e- times 1.67262e-27 over 1 p



chem - bobpursley, Tuesday, September 21, 2010 at 6:48pm
That is what I would do also. But I think you ought to know why that is the method.

figure number electrons in 1.5g:
number electrons: .0015kg/9.11E-31

now figure the mass of the same number of protons:
1.67E-27kg*(.0015/9.11E-31)



chem - Sara, Tuesday, September 21, 2010 at 6:50pm
do i add the e-27 and e-31. i forget



chem - bobpursley, Tuesday, September 21, 2010 at 6:56pm
a^b/a^c= a^(b-c)



chem - Sara, Tuesday, September 21, 2010 at 6:59pm
what? sry im not getting this...



chem - Sara, Tuesday, September 21, 2010 at 8:30pm
so i got 8.087535951e20 kg. my anser is suppose to be in grams so would it be 8087.535951e17?

does this sound right/what u got?

thanks

  • Chem- bobpursley -

    1.67E-27kg*(.0015/9.11E-31) =2.75
    so three protons.

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