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write the net ionic equation for the following :
2CuCl(aq)-> CuCl2(aq)+ Cu(s)

4NaCl(aq)+2H2SO4(aq)+MnO2(s)-> 2Na2SO4(aq)+2H2O(l)+Cl2(g)

3KOH(aq)+Fe(NO3)3(aq)->Fe(OH)3(s)+ 3KNO3(aq)

  • chemistry -

    I don't believe #1 since CuCl is not very soluble in water; however, since it "says" aq, we will do it as is.
    2CuCl(aq) --> CuCl2(aq) + Cu(s)

    2Cu^+(aq) + 2Cl^-(aq) ==>Cu^+2(aq) + 2Cl^-(aq) + Cu(s)

    Now cancel ions common to both sides (Cl^-) to arrive at the net equation.
    2Cu^+(aq) ==>Cu^+2(aq) + Cu(s)

    Do the others the same way.
    1. Balance the molecular equation.
    2. Convert to the ionic equation. Solids are written as the molecule, weak electrolytes (such as water, etc) are written as the molecule, gases are written as the molecule. All others are written as ions.
    3. Cancel ions common to both sides to arrive at the net ionic equation.

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