Math
posted by Isabel .
If i'm given the equation
4.23= .19t^2+2.56t2.37
how do i find the value of t?

Put the equation into the form
ax^2 + bx + c = 0
then use the quadratic formula to find the solutions. 
Rewrite it in standard quadratic form as:
0.19t^2  2.56 t +6.60 = 0
The coefficients and constant are:
a = 0.19
b = 2.56
c = 6.6
Then use the quadratic formula for the two roots:
t = [b +/1 sqrt(b^24ac)]/2a
One of the solutions is exactly 10.
The other is 3.4737