Math
posted by Neee .
Simplify:
f(x)=sqrt (16x^4)/ sinx
This is to evaluate a limit, but I don't know if I can simplify the above equation. Because I tried to get rid of the radical in the numerator but I ended up with a radical in the denominator. >< Help

Post the entire limit question. Is the Sin in the sqrt or is it (sqrt(_))/sinx

Where is f(x)=(sqrt(164^4))/sinx continuous? Evaluate lim x> pi/2 f(x)

sqrt(16x^4)/sinx
as x>PI/2
Then limit is easy...
Lim = sqrt(16(pi/2)^4)/1
I don't see the problem.
Now, where is it continous?
when 16x^4 goes negative, there is a problem with a sqrt of a negative number, so when x=2, there is a disconituity as the f(x)=0 .