Algebra

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(d+8/d-9)divided by 9d+72/c-7

Can anyone point me in the right direction to solving this problem? Thank you

  • Algebra -

    Your nonuse of grouping symbols is annoying.

    I think you meant this:

    (d+8)/(d-9) divided by (9d+72)/(c-7)

    well, multiplication is reciprocal of division, so your problem becomes
    (d+8)/(d-9) multiplied by (c-7)/(9d-72)
    or

    (d+8)(9d-72)/((d-9)(c-7) or

    9(d+8)(d-9)/((d-9)(c-7)) or
    9(d+8)/(c-7)

  • Algebra -

    Thank you for your help sir.

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