Algebra

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Square lot. Sam has a lot that he thought was a square, 200 feet by 200 feet. When he had it surveyed, he discovered that one side was x feet longer than he thought and that the other side was x feet shorter than he thought.
a).
Find a polynomial A(x) that represents the new area.
b).
Find A(2)
c).
If x=2 feet then how much less area does he have than he thought he had?
Answer:
a).
A(x)=(200-x)*(200+x)
A(x)=40,000-x^2
b).
A(2)=40,000-(2)^2
A(2)=40,000-4
A(2)=39,996 feet^2
c).
Initial area= 200*200=40,000 feet^2
Present area A(2)=39,996 feet^2
40,000 – 39,996= 4 feet ^2
I need to know if i done this correctly.

  • Algebra -

    All of your answers are correct, and
    you did a good job of showing your
    work. Good job!!

  • Algebra -

    Thank you so much!

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