algebra 1
posted by no one needs to know .
how do you solve the following questions using the substitution method?
3xy=3 3x+6y=48
3x5y=21 5x+6y=32
2x+4y=12
4x+16y=8

Substitution? I would solve for x in the first equation:
x=62y check that. Then put that for x into the second equation...
4(62y)+16y=8 and solve for y.