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A 50g ice cube is added to 110g of water in a 62g aluminum cup. The water and cup initially have a temperature of 23°C. Find the initial temperature of the ice cube such that all of the water is just turned to ice. Use the following specific heats: water = 4186 J/(kg•K), ice = 2090 J/(kg•K), and aluminum = 900 J/(kg•K). The latent heat of fusion for water is 33.5e4 J/kg

  • physics -

    find the heat needed...

    Heatneeded=masswater*c(0-23)-masswater*Lf+massAl*Cal*(0-23)
    Notice this heat is "negative), meaning it was lost. (it is negative heat gained).

    now, the heat the ice gained.

    massice*Cice*(0-Ti)

    Now add the heats gained...set to zero.

    heat ice gained+heat water(and aluminum) gaied [remember this is negative] =0
    solve for Ti

  • physics -

    97.93 celcius

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