Equation
posted by Lisa D .
w2  2w + 2 = 0
Use the discriminant to determine how many realnumber solutions the equation has
A.2
B.1
C.0

Equation 
Jen
The discriminant is b^24ac. For the equation you posted, a=1 (the coefficient on w^2), b=2, and c=2. Plug those numbers in. If the number you get is positive, there are 2 real number solutions. If you get zero, there is 1 solution. If you get a negative number, there are no solutions. Post your answer if you want it checked.

Equation 
bobpursley
Actually, if you get a negative discriminant, you get no real solutions, but insteady, you get complex (in the imaginary domain) solutions, that in general, are valid.
eg. x^2+0x+1=0
the discriminate is sqrt(4)
and in fact, then the solution is
x= + i 
Equation 
Lisa D
Is the answer 0 not sure if this is correct.

Equation 
Jen
Show me your work. You have to plug in the numbers.
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