# fintemath

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dimension of a floor; the perimeter of a rectangular floor is 90ft. find the dimensions of the floor if the length is twice the width

• fintemath -

P = 2L + 2W

90 = 4W + 2W
90 = 6W
15 = W

Check:

15 + 15 + 30 + 30 = 90

• fintemath -

i know 90 is the perimeter but where did the 4W + 2W come from?

• finitemath -

This is the formula for a perimeter.

P = 2L + 2W

Your problem states that the length is twice the width. Therefore, L = 2W

• fintemath -

what happened to 2L? sorry for my dumb question.

• fintemath -

oh nevermind.. i got it. thanks for helping me Ms. Sue (:

• fintemath -

You're welcome, Sha.

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