Chemistry

posted by .

My mind is bleeding again. I am trying to figure out the molarity of acetic acid in Vinegar. We used a standard solution of .613 Molars of NaOH. We added 33.75mL of NaOH to completely titrate/neutralize 25mL of Vinegar and we're supposed to be able to figure out the molarity of acidic acid in the vinegar, but I cannot figure this out. Can anybody help me?

  • Chemistry -

    moles NaOH = M x L = 0.613 x 0.03375= ??

    So moles acidity in the solution (the vinegar) is the same as moos NaOH since the reaction is a 1 mole to 1 mole ratio.

    Since moles vinegar is in 25 mL, then
    M = moles/L and M vinegar = moles from above/0.025 = ??

    OR, if you don't want to go through all the explanations, just use this neat formula (good when 1:1 mole ratio exists as it does in this problem).
    mL NaOH x M NaOH = mL vinegar x M vinegar.

    Solve for M vinegar.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Gen. Chemistry lab

    Trying to find mass percent of acetic acid in 25 drops of .683M NaOH solution are required to neutralize 10 drops of cleaning vinegar. Assume that the density of the cleaning vinegar is the same as the density of regular vinegar which …
  2. chemistry

    Could someone help me with this please? In chemistry, we did a lab in which he put brands of commerical vinegar in a microplate. We put in 10 drops of each vinegar in each plate thinger then we added 1 drop of phenolphthalein and then
  3. Chemistry

    A sample of 25.00 mL of vinegar is titrated with a standard 1.02 M NaOH solution. It was found that a volume of 19.60 mL of the standard NaOH solution is used to completely neutralize the acetic acid in the solution. Calculate the …
  4. chem-acid-base titrations

    Acetic acid (HC2H3O2) is an important component of vinegar. A 10.00mL sample of vinegar is titrated with .5052 M NaOH, and 16.88 mL are required to neutralize the acetic acid that is present. a.write a balanced equation for this neutralization …
  5. chemistry

    a 10.0mL vinegar sample was completely neutralized by 22.5mL 0.2M NaOH solution. calculate molarity and % of acetic acid in vinegar. please help
  6. chemistry

    4. Vinegar is a dilute solution of acetic acid. What is the concentration of acetic acid in the vinegar if 26.5 mL of NaOH at 0.250 M are required to neutralize 10.0 mL of vinegar?
  7. Chemistry

    Vinegar is a dilute solution of acetic acid. What is the concentration of acetic acid in the vinegar if 26.5 mL of NaOH at 0.250 M are required to neutralize 10.0 mL of vinegar?
  8. chemistry

    Titration was used to determine the molarity of acetic acid in vinegar. A primary standard solution of KHP was used to standardize the NaOH. 1. When performing this experiment, impure KHP was used to standardize the NaOH solution. …
  9. chemistry

    2. When preparing a NaOH solution, a student did not allow the NaOH pellets to completely dissolve before standardizing the solution with KHP. However, by the time the student refilled the buret with NaOH to titrate the acetic …
  10. Chemistry

    In this experiment NaOH is standardized to find out the percent by mass of the acetic acid in a sample of vinegar. A student had not allowed the NaOH pellets to dissolve completely before standardizing it with KHP, but when the student …

More Similar Questions