I need help with this equation, I am really bad at fractions.
m^2 - (49/2 * m)= 1/2
You can always "get rid" of fractions by multiplying each term by the LCD of your fractions.
so multiply each term by 2 to get
2m^2 - 49m = 1
can you handle that quadratic?
yes thank you, I think I got it
To solve the equation m^2 - (49/2 * m) = 1/2, we need to first simplify the equation by combining like terms.
Step 1: Distribute the fraction (49/2) to the variable m:
m^2 - (49/2 * m) = 1/2
Simplifying this gives us:
m^2 - (49m/2) = 1/2
Step 2: To eliminate the fractions, we can multiply the entire equation by the common denominator of 2.
2 * (m^2 - (49m/2)) = 2 * (1/2)
This simplifies to:
2m^2 - 49m = 1
Step 3: Rearrange the equation to make it quadratic in form:
2m^2 - 49m - 1 = 0
Now, to solve this quadratic equation, we can use the quadratic formula:
m = (-b ± √(b^2 - 4ac)) / (2a)
For our equation, a = 2, b = -49, and c = -1. Substituting these values into the quadratic formula, we get:
m = (-(-49) ± √((-49)^2 - 4 * 2 * -1)) / (2 * 2)
Simplifying this equation will give us the roots for m.