posted by Anonymous .
What volume of oxygen is needed to react with solid sulfur to form 6.20 L of sulfur dioxide?
Write the equation and balance it.
S + O2 ==> SO2 (Or your teacher may prefer that you write it as
S8 + O2 ==> SO2.
Convert 6.20 L SO2 to moles. 6.20 x (1 mol/22.4 L) = ??
Using the coefficients in the balanced equation, convert mols SO2 to moles O2.
Now convert moles O2 to liters. L = moles x 22.4 L/mol = ??
its 6.20 L
the answer is 6.20 L