MathProbability
posted by Fred .
The question is to draw two cards from a standard deck without replacement. To win, both cards must be face cards. What is the probability you will LOSE?
I know how to use complement to get the answer. Why does P(Not face)* P(Not face) produce a different and wrong answer?

MathProbability 
PsyDAG
If both have to be face cards, then the probability of losing will include either the probability of one or both not being a face card.
P(face) * P(not face) + P(not face) * P(not face) = ? 
MathProbability 
Fred
Thank you. Now I know what I forgot. There are two ways of P(face)*P(not face) then add P(not face)* P(not face)
Went brain dead.
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