college algebra
posted by JohnJ .
3y^2+8=0
(3y+2)+(3y2)=8+0
3y=8
y=3/8
Radical and Rational Exponent
this chapter is hard for me.

college algebra 
bobpursley
No, it is wrong.
3y^2=8
y^2=8/3
Now you can't to anymore in the real number system, as there is no such thing as a square root of a negative number. But if you define i as sqrt (1), then
y=+ sqrt (8/3) * i
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