Physics
posted by Marium .
Q)1 : Alpha particles travel through a magnetic field of 0.360T and are deflected in an arc of 0.0820m. Assuming the alpha particle are perpendicular to the field, what is the energy of an individual alpha particle?

calculate the velocity:
Bqv=Force
and force= massalpha*v^2/r
bqv=massv^2/r
solve for v. 
do i use the value of q/m ratio??
and thank u =) 
Magnetic field B = 0.36 T
Deflected radius of an arc r = 0.082 m
Charge of alpha particle q = 2e = 3.20435 × 10^19 C
Mass of alpha particle m = 6.64 × 10^−27 kg
Magnetic Force = Bqv
Centripetal Force = mv²/r
Bqv = mv²/r
v = Bqr/m
v = (0.36)( 3.20435 × 10^19)( 0.082) / (6.64 × 10^−27)
v = 1.42458 × 10^6 m/s
Energy of alpha particle E = (1/2)mv²
E = (1/2)( 6.64 × 10−27)( 1.42458 × 106)²
E = 4.7296 × 10^−15 J
Energy of alpha particle is 4.7296 × 10^−15 J.
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