Geraniol is a compound found in rose oil that is used in perfumes. What is the molas mass of geraniol if its vapor has a density of 0.480 g/L at a temperature of 260.0 degrees Celsius and a pressure of 0.140 atm???
Hope this helps!!!
D= 0.480 g/l
T= 260.0°C+ 273= 533K
P= 0.140 ATM
R(constant; always 0.08206)
M(molar mass)= DRT/P
M= 0.480× 0.08206× 533/ 0.140= 149.96 g/mol
Molar mass of geraniol= 149.96 g/mol
Sorry, I didn't notice that. The problem gives density so we take PV = nRT and work on it.
Since n = grams/molar mass we substitute to obtain
PV = gRT/molar mass and
pV*molar mass = gRT, then
P*molar mass = (g/V)RT but g/V = density so
p*molar mass = density*RT
That should help.
The answer is correct sir
Use PV = nRT
Solve for n= number of moles.
Then n = grams/molar mass. Solve for molar mass.
Thank you!!
To find the molar mass of geraniol, we need to use the ideal gas law equation:
PV = nRT
where:
P = pressure in atm
V = volume in L
n = number of moles
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature in Kelvin
First, let's convert the given temperature from degrees Celsius to Kelvin:
T(K) = 260.0°C + 273.15 = 533.15 K
Next, let's rearrange the ideal gas law equation to solve for n (number of moles):
n = PV / RT
Now, we need to convert the given density of the vapor into molar concentration (moles per liter) using the equation:
density = mass / volume
Here, molar concentration = mass / molar mass, so we can rewrite the equation as:
density = (molar mass / molar volume) / volume
Since the molar volume is equal to the molar mass divided by the molar density (Avogadro's number), we can simplify the equation as:
density = (molar mass * Avogadro's number) / volume
Rearranging this equation, we get:
molar mass = (density * volume) / Avogadro's number
Now, let's substitute the given values into the equation:
density = 0.480 g/L
volume = 1 L (since the density is given per liter)
Avogadro's number = 6.022 × 10^23 mol^-1 (known constant)
molar mass = (0.480 g/L * 1 L) / 6.022 × 10^23 mol^-1
Simplifying further, we get:
molar mass ≈ 7.96 × 10^-23 g/mol
Therefore, the molar mass of geraniol is approximately 7.96 × 10^-23 g/mol.