For the reaction NaOH + HCl---> H20 + NaCl where the mass of NaOH is 2g and the Volume of Hcl is 100ml with a concentration of 0.5 mol/l. The initial temp is 25 and the final is 35, what is the amount of energy absorbed by the solution?
q = mass water x specific heat water x delta T.
To determine the amount of energy absorbed by the solution in this reaction, we need to calculate the heat transferred during the process.
The heat transfer equation is given by:
q = mcΔT
Where,
q is the heat transferred,
m is the mass of the solution,
c is the specific heat capacity of the solution,
ΔT is the change in temperature.
First, let's find the mass of the solution. Since the only substance given is NaOH, we can assume that the volume of HCl provided will react completely with the NaOH to form the solution.
Given: Volume of HCl = 100 ml
Density of HCl = 1 g/mL (approximately)
So, the mass of the solution would be:
Mass of HCl = Volume of HCl x Density of HCl
= 100 ml x 1 g/ml
= 100 g
Next, let's find the change in temperature (ΔT):
Initial temperature = 25 °C
Final temperature = 35 °C
ΔT = Final temperature - Initial temperature
= 35 °C - 25 °C
= 10 °C
Now we need to determine the specific heat capacity of the solution. Since we are not given the exact composition of the solution, we can approximate it as the specific heat capacity of water (c = 4.18 J/g·°C).
Finally, we can substitute these values into the heat transfer equation:
q = mcΔT
= (mass of the solution) x (specific heat capacity) x (change in temperature)
= 100 g x 4.18 J/g·°C x 10 °C
= 4180 J
Therefore, the amount of energy absorbed by the solution is 4180 Joules (J).