# Calculus II

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How do you integrate the function -- > sinx (4^cosx) from 0 to pi/2

I did "u-substitution" to make it the integral from 1 to 0 of 4^u but then i don 't know where to go from there! Thank you

• Calculus II -

INT 4^u du

what is the integral of a^u du?

Ans: a^u / lna

check that.

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