Consider a bowl containing 36 different slips of paper. Ten of the slips of paper each contain one of 16)
the digits from the set 0 through 9 and 26 slips each contain one of the 26 letters of the alphabet. If
one slip is drawn at random, what is P(odd number or a consonant)?
21 consonants and 5 odd numbers. Would my answer be 21/36 + 5/36= 26/36
I am given a choice for answers: A)0, B) 21/36, C) 5/36 D) 26/36
correct
To calculate the probability of drawing an odd number or a consonant from the bowl, you first need to determine the total number of outcomes and the number of successful outcomes.
Total Number of Outcomes:
The bowl contains 36 slips of paper, so there are 36 possible outcomes.
Number of Successful Outcomes:
There are 21 consonants in the bowl, so there are 21 successful outcomes for selecting a consonant.
There are 5 odd numbers in the bowl, so there are 5 successful outcomes for selecting an odd number.
Now, you can calculate the probability:
P(odd number or a consonant) = (Number of Successful Outcomes) / (Total Number of Outcomes)
= (21 + 5) / 36
= 26 / 36
= 13 / 18
Therefore, the correct answer is D) 26/36.