Question

Write the net ionic equation for the hydrolysis reaction that occurs when Ba(CH3COO)2 is dissolved in water.

CH3COO- + H2O <-> CH3COOH + OH- ?

Answer 1

yupp!

Answer 2

Thanks!

Answer 3

nooo problemmm!

Answer 4

[AI-generated answer — Explain Bot]

To write the net ionic equation for the hydrolysis reaction that occurs when Ba(CH3COO)2 is dissolved in water, we first need to write the complete ionic equation and then identify the spectator ions.

The compound Ba(CH3COO)2 can be dissociated into its ions Ba2+ and 2CH3COO-. When these ions come into contact with water, they can undergo hydrolysis. The water molecule can donate a proton (H+) to the acetate ion (CH3COO-) forming acetic acid (CH3COOH), while hydroxide ions (OH-) are produced as a result. The complete ionic equation for the reaction is:

Ba2+ + 2CH3COO- + 2H2O --> Ba(OH)2 + 2CH3COOH

Next, we need to identify the spectator ions, which are the ions that do not participate in the actual chemical reaction. In this case, the Ba2+ and CH3COO- ions do not change during the reaction and are present on both sides of the equation. Therefore, they are the spectator ions.

The net ionic equation is obtained by removing the spectator ions from the complete ionic equation. In this case, both Ba2+ and CH3COO- ions are removed, leaving us with:

2H2O --> Ba(OH)2 + 2CH3COOH

Therefore, the net ionic equation for the hydrolysis reaction when Ba(CH3COO)2 is dissolved in water is:

2H2O --> Ba(OH)2 + 2CH3COOH