posted by Kate .
Hi i don't know how to do this problem
solve for n^3
given that log(40 SQRT(3))/log(4n) = log(45)/log(3n)
Thanks i'm copletely lost and don't know how to solve
let a=log(40 sqrt(3)) and b=log45
then take the antilog of both sides, it looks like fun.
how did you go from this
You are supposed to fill in the blanks.
well if follow now but don't know how to take the anti log of that mumbo jumbo
n = 10^(3((blog4-alog3)/(a-b) )
im unsure how that simplifies