In the figure below, a box of Cheerios (mass mC = 0.8 kg) and a box of Wheaties (mass mW = 2.5 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.0 N, and the magnitude of the frictional force on the Wheaties box is 3.2 N. If the magnitude of is 12 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?

Question

In the figure below, a box of Cheerios (mass mC = 0.8 kg) and a box of Wheaties (mass mW = 2.5 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.0 N, and the magnitude of the frictional force on the Wheaties box is 3.2 N. If the magnitude of is 12 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?

Answer 1

if the magnitude of is ???

Answer 2

In the figure below, a box of Cheerios (mass mC = 0.8 kg) and a box of Wheaties (mass mW = 2.5 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.0 N, and the magnitude of the frictional force on the Wheaties box is 3.2 N. If the magnitude of is 12 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?

Answer 3

To find the magnitude of the force on the Wheaties box from the Cheerios box, we need to consider the forces acting on both boxes and use Newton's second law of motion.

Let's denote the force on the Cheerios box as Fc and the force on the Wheaties box as Fw.

The equation for the net force on an object is given by:

ΣF = ma

Where ΣF is the sum of all the forces acting on the object, m is the mass of the object, and a is the acceleration of the object.

For the Cheerios box:

ΣFc = Fc - frictional force on the Cheerios box

For the Wheaties box:

ΣFw = Fw - frictional force on the Wheaties box

Now, using the given information:

Frictional force on the Cheerios box = 2.0 N
Frictional force on the Wheaties box = 3.2 N
Magnitude of the applied force = 12 N
Mass of the Cheerios box = 0.8 kg
Mass of the Wheaties box = 2.5 kg

For the Cheerios box:

ΣFc = Fc - 2.0 N

For the Wheaties box:

ΣFw = Fw - 3.2 N

Since the force applied is the same for both boxes:

ΣFc = ΣFw = 12 N

Now, let's solve the equations to find Fw:

12 N - 2.0 N = Fw - 3.2 N

Simplifying the equation:

10 N = Fw - 3.2 N

By rearranging the equation:

Fw = 10 N + 3.2 N

Fw = 13.2 N

Therefore, the magnitude of the force on the Wheaties box from the Cheerios box is 13.2 N.

if the magnitude of is ???

FML

To find the magnitude of the force on the Wheaties box from the Cheerios box, we need to consider the forces acting on both boxes and use Newton's second law of motion.