0 = x (x - 6.19) (x - s) if you have that, and you wanna find that last zero (root) how do you do it?
To find the last zero or root of the equation \(0 = x(x - 6.19)(x - s)\), where \(s\) is a constant, you can use the zero product property. The zero product property states that if a product of factors is equal to zero, then at least one of the factors must be zero.
In this case, the equation is already set to zero, so you can set each factor equal to zero and solve for the value of \(x\) that makes each factor zero.
1. Set \(x = 0\):
Substitute \(x = 0\) into the equation to get:
\(0 = 0(0 - 6.19)(0 - s)\)
Since the first factor is zero, this equation is satisfied regardless of the value of \(s\). However, this does not give us a specific value for \(x\).
2. Set \(x - 6.19 = 0\):
Solve for \(x\) by adding \(6.19\) to both sides of the equation:
\(6.19 = x\)
This gives us \(x = 6.19\).
3. Set \(x - s = 0\):
Solve for \(x\) by adding \(s\) to both sides of the equation:
\(s = x\)
This gives us \(x = s\).
So, from the equation \(0 = x(x - 6.19)(x - s)\), we have two additional roots: \(x = 6.19\) and \(x = s\), where \(s\) is the constant value.
Note: To find the value of \(s\) or any other specific root, you would need additional information or constraints from the problem or context.