Pre-Algebra

posted by .

3k/5+44=12k/25+8

  • Pre-Algebra -

    Multiply both sides by 25.

    15k + 1100 = 12k + 200

    Subtract 12k and 1100 from both sides.

    3k = 900

    Can you divide both sides by 3?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Algebra (new one since I put "match" (bad speller)

    I have a few match problems that I can't figure out. 1.solve: 3x+5=x√7 (that's a radical sign) 2.factor: (2k+3)2-(2x+3)(y-2)-20(y-2)2 (the "2" after (2k+3) ans (y-2) is suppose to be a square sign. thanks if you can help, or …
  2. Algebra

    ((k^2+6k+9)/(k^2+12k+27))×(k^2+9)/((k^2+12k+27)) express in lowest terms
  3. Algebra - for bobpursley

    Problem given: 14-4(2k+4) = -2(4-3k) 14-8k-16 = -8+12k -8k-2 = -8+12k plus 8k to each side ~~> -2 = -8+20k plus 8 to each side ~~>6 = 20k divide both sides by 20 ~~> 3/10 = k
  4. ALGEBRA

    Multiply: (K+3)/(4K-2)*(12K^2 + 2k – 4) • 3(k+3)/(3k+2) • 3(k+3)(2k-1)/2 • (x-5)(3x+2) • (x-5)(12x+8) How?
  5. algebra--1 question

    Multiply. (k+3)/(4k-2)*(12k^2+2k-4) a. 3(k+3)/3k+2 b. 3(k+3)(2k-1)/2 c. (k+3)(3k+2)*** d. (3k+1)(2k+3) Please help?
  6. Pre Algebra

    5. (m^2-m-3)+(m-4) A. m^2+m-1 B. m^2+2m-7 C. m^2-7 D. m^2-1 6. (4x^2-2x-1)-(-3x^3+2) A. -3x^3+4x^2-2x+1 B. -3x^3+4x^2-2x-3 C. 3x^3+4x^2-2x+1 D. 3x^3+4x^2-2x-3 9. 100^12/100^8 A. 100^12/8 B. 100^96 C. 100^4*** D. 100^20 16. (1.1*10^-5)(3*10^-2) …
  7. Pre-Algrebra

    3. 2x^2+6x-7x+8-3x^2+1 A. 2x^2+x+9 B. -2x^2-x-9 C. -x^2-x+9 D. x^2+9 4. What are the coefficents in the polynomial 4x^2+3x-3 A. 4,-3,-3 B. 4,3 C. 4,3,3 D. -4,-3 6. (7x^2-x-2)-(6x^3+3) A. 6x^3-+7x^2-x-5 B. -6x^3+7x^2-x+1 C. -x^3-x-5 …
  8. Math

    3. 2x^2+6x-7x+8-3x^2+1 A. 2x^2+x+9 B. -2x^2-x-9 C. -x^2-x+9 D. x^2+9 4. What are the coefficents in the polynomial 4x^2+3x-3 A. 4,-3,-3 B. 4,3 C. 4,3,3 D. -4,-3 6. (7x^2-x-2)-(6x^3+3) A. 6x^3-+7x^2-x-5 B. -6x^3+7x^2-x+1 C. -x^3-x-5 …
  9. math

    19. 4k^2(-3k^2-4k+5) A. -12k^4-16k^3+20k^2 B. 12k^4-16k^3=9k^2 C. -12k^3+20k ** D. k^4+9k^2
  10. Mathematics

    How do you solve 12k^2m^8/4km^5 This is what I thought of doing: =12k^2m^8/4km^5 =8km^3 *Is that correct?

More Similar Questions