Use factoring to solve the equation.
(x+6)(x+5)=2
(x+6)(x+5)=2
x^2 + 11x + 30 - 2 = 0
x^2 + 11x + 28 = 0
(x+4)(x+7) = 0
x = -4 or x = -7
(x+6)(x+5)=2 multiply x by x and x by 5
and 6 by x and 6 by 5 so u get x^2+5x+6x+30=2 2-30 x^2+5x+6x=-28 that's as far as i can get lol hope it helps
To solve the equation (x+6)(x+5) = 2 using factoring, we need to figure out what values of x make the left-hand side of the equation equal to 2.
First, let's expand the equation:
(x+6)(x+5) = 2
x^2 + 6x + 5x + 30 = 2
x^2 + 11x + 30 = 2
Now, let's rearrange the equation to have it equal to zero:
x^2 + 11x + 30 - 2 = 0
x^2 + 11x + 28 = 0
To solve this quadratic equation by factoring, we need to find two numbers that multiply to get 28 (the constant term) and add up to 11 (the coefficient of x).
The numbers that fit these conditions are 4 and 7:
(x + 4)(x + 7) = 0
Now, we can set each factor equal to zero and solve for x:
x + 4 = 0 => x = -4
x + 7 = 0 => x = -7
So, the solutions to the equation (x+6)(x+5) = 2 are x = -4 and x = -7.