posted by Edwin .
Find the vector eqn which passes through (1,1,2) and is parallel to the vector which is perpendicular to both 2i+2j-k and -3i+2j+k
take the cross-product to (2,2,-1) and(-3,2,1)
which is (4,1,10)
So your line must have that directions
so the vector equation is
r = (1,1,2) + k(4,1,10)