the perimeter is 48, the length is 2 times the with. what is the width and length. I got the answer but how do you figure it out, is it a formula?
What shape are you dealing with?
A rectangle?
If so, then perimeter = 2L + 2w
let the width be W
"the length is 2 times the with" ---> l = 2w
so 2L + 2(2w) = 48
6w = 48
w = 8
then l= 16
P = 4W + 2W
48 = 6W
8 = W
To find the width and length of a rectangle with a given perimeter and a specific relationship between the length and width, you don't need to use a formula but rather a system of equations.
Let's denote the width as "w" and the length as "l". We know two things:
1. The perimeter is given as 48. The formula for the perimeter of a rectangle is: Perimeter = 2 * (length + width). So, we can write the equation as: 48 = 2 * (l + w).
2. The length is two times the width. Mathematically, this can be written as: l = 2w.
Now, we have two equations:
Equation 1: 48 = 2 * (l + w)
Equation 2: l = 2w
To solve this system, we can substitute the value of l from Equation 2 into Equation 1:
48 = 2 * (2w + w)
48 = 2 * 3w
48 = 6w
Next, we can isolate w by dividing both sides of the equation by 6:
48 / 6 = w
8 = w
So, the width (w) is 8 units.
To find the length (l), we can substitute the value of w back into Equation 2:
l = 2w
l = 2 * 8
l = 16
Therefore, the width is 8 units and the length is 16 units.